Theorems · Theorem · commutative algebra
Algebra.Smooth.exists_subalgebra_fg
∀ (R : Type u_1) [inst : CommRing R] (A : Type u) (B : Type u_2) [inst_1 : CommRing A] [inst_2 : Algebra R A] [inst_3 : CommRing B] [inst_4 : Algebra A B] [Algebra.Smooth A B], ∃ A₀ B₀ x x_1, A₀.FG ∧ Algebra.Smooth (↥A₀) B₀ ∧ Nonempty (B ≃ₐ[A] TensorProduct (↥A₀) A B₀)
Let A be an R-algebra. If B is a smooth A-algebra, there exists an
R-subalgebra of finite type A₀ of A and a smooth A₀-algebra B₀ such that
B ≃ₐ A ⊗[A₀] B₀.
See Algebra.Smooth.exists_finiteType for a version in terms of Function.Injective.
- Cited by
- 2 results in Mathlib
- Foundations
- Depth 130 from the axioms · uses propext, Classical.choice, Quot.sound
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Cites50
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
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Cited by2
Results whose statement or proof uses this declaration.
- Algebra.Smooth.exists_subalgebra_finiteTypeproof · cited by 0
- Algebra.Smooth.exists_finiteTypeproof · cited by 0