Theorems · Inductive type · algebraic geometry
AlgebraicGeometry.IsSchemeTheoreticallyDominant
{X Y : AlgebraicGeometry.Scheme} → (X ⟶ Y) → PropA morphism is scheme-theoretically dominant if its kernel is trivial.
- Cited by
- 9 results in Mathlib
- Foundations
- Depth 99 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites2
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Quiver.Homstatement · cited by 32,603
- AlgebraicGeometry.Schemestatement · cited by 2,540
Cited by11
Results whose statement or proof uses this declaration.
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.casesOnstatement and proof · cited by 1
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.isReducedstatement and proof · cited by 1
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.ker_eq_botstatement and proof · cited by 1
- AlgebraicGeometry.Scheme.Hom.app_injectivestatement and proof · cited by 1
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.of_isDominantstatement · cited by 1
- AlgebraicGeometry.Scheme.Hom.ker_eq_botstatement · cited by 1
- AlgebraicGeometry.isSchemeTheoreticallyDominant_iffstatement and proof · cited by 1
- AlgebraicGeometry.isSchemeTheoreticallyDominant_iff_isDominantstatement and proof · cited by 1
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.of_isPullbackstatement and proof · cited by 0
- AlgebraicGeometry.IsSchemeTheoreticallyDominant.recOnstatement and proof · cited by 0