Theorems · Inductive type · algebraic geometry
AlgebraicGeometry.Scheme.RationalMap.IsOver
{X Y : AlgebraicGeometry.Scheme} → (S : AlgebraicGeometry.Scheme) → [X.Over S] → [Y.Over S] → X.RationalMap Y → PropA rational map is an S-map if some partial map in the equivalence class is an S-map.
- Cited by
- 5 results in Mathlib
- Foundations
- Depth 148 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites3
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- AlgebraicGeometry.Schemestatement · cited by 2,540
- AlgebraicGeometry.Scheme.Overstatement · cited by 35
- AlgebraicGeometry.Scheme.RationalMapstatement · cited by 25
Cited by8
Results whose statement or proof uses this declaration.
- AlgebraicGeometry.Scheme.RationalMap.IsOver.exists_partialMap_overstatement and proof · cited by 2
- AlgebraicGeometry.Scheme.PartialMap.exists_restrict_isOverstatement and proof · cited by 1
- AlgebraicGeometry.Scheme.RationalMap.exists_partialMap_overstatement and proof · cited by 1
- AlgebraicGeometry.Scheme.RationalMap.isOver_iffstatement and proof · cited by 0
- AlgebraicGeometry.Scheme.PartialMap.isOver_toRationalMap_iff_of_isSeparatedstatement and proof · cited by 0
- AlgebraicGeometry.Scheme.RationalMap.IsOver.casesOnstatement and proof · cited by 0
- AlgebraicGeometry.Scheme.RationalMap.equivFunctionFieldOverstatement · cited by 0
- AlgebraicGeometry.Scheme.RationalMap.IsOver.recOnstatement and proof · cited by 0