Theorems · Theorem · category theory
CategoryTheory.Arrow.square_from_iso_invert
∀ {T : Type u} [inst : CategoryTheory.Category.{v, u} T] {X Y : T} (i : X ≅ Y) (p : CategoryTheory.Arrow T)
(sq : CategoryTheory.Arrow.mk i.hom ⟶ p),
CategoryTheory.CategoryStruct.comp i.inv
(CategoryTheory.CategoryStruct.comp (CategoryTheory.Arrow.Hom.left sq) p.hom) =
CategoryTheory.Arrow.Hom.right sqGiven a square from an isomorphism i to an arrow p, express the target part of sq
in terms of the inverse of i.
- Defined in
- Mathlib.CategoryTheory.Comma.Arrow
- Cited by
- 0 results in Mathlib
- Foundations
- Depth 16 from the axioms · uses propext, Quot.sound
- Assumes
- CategoryTheory.Category
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Cites15
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- CategoryTheory.Categorystatement and proof · cited by 32,673
- Quiver.Homstatement and proof · cited by 32,603
- CategoryTheory.CategoryStruct.compstatement and proof · cited by 17,999
- CategoryTheory.Iso.homstatement and proof · cited by 7,684
- CategoryTheory.Iso.invstatement and proof · cited by 6,514
- CategoryTheory.Isostatement and proof · cited by 3,963
- CategoryTheory.Arrowstatement and proof · cited by 713
- CategoryTheory.Arrow.leftstatement · cited by 426
- CategoryTheory.Arrow.rightstatement · cited by 423
- CategoryTheory.Arrow.mkstatement and proof · cited by 421
- CategoryTheory.Arrow.homstatement · cited by 335
- CategoryTheory.Iso.inv_hom_id_assocproof · cited by 275
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