Theorems · Definition · category theory
CategoryTheory.Biprod.gaussian
{C : Type u} →
[inst : CategoryTheory.Category.{v, u} C] →
[inst_1 : CategoryTheory.Preadditive C] →
[inst_2 : CategoryTheory.Limits.HasBinaryBiproducts C] →
{X₁ X₂ Y₁ Y₂ : C} →
(f : X₁ ⊞ X₂ ⟶ Y₁ ⊞ Y₂) →
[CategoryTheory.IsIso
(CategoryTheory.CategoryStruct.comp CategoryTheory.Limits.biprod.inl
(CategoryTheory.CategoryStruct.comp f CategoryTheory.Limits.biprod.fst))] →
(L : X₁ ⊞ X₂ ≅ X₁ ⊞ X₂) ×'
(R : Y₁ ⊞ Y₂ ≅ Y₁ ⊞ Y₂) ×'
(g₂₂ : X₂ ⟶ Y₂) ×'
CategoryTheory.CategoryStruct.comp L.hom (CategoryTheory.CategoryStruct.comp f R.hom) =
CategoryTheory.Limits.biprod.map
(CategoryTheory.CategoryStruct.comp CategoryTheory.Limits.biprod.inl
(CategoryTheory.CategoryStruct.comp f CategoryTheory.Limits.biprod.fst))
g₂₂If f is a morphism X₁ ⊞ X₂ ⟶ Y₁ ⊞ Y₂ whose X₁ ⟶ Y₁ entry is an isomorphism,
then we can construct isomorphisms L : X₁ ⊞ X₂ ≅ X₁ ⊞ X₂ and R : Y₁ ⊞ Y₂ ≅ Y₁ ⊞ Y₂
so that L.hom ≫ g ≫ R.hom is diagonal (with X₁ ⟶ Y₁ component still f),
via Gaussian elimination.
- Cited by
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- Foundations
- Depth 36 from the axioms · uses propext, Classical.choice, Quot.sound
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Cites16
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- CategoryTheory.Categorystatement and proof · cited by 32,673
- Quiver.Homstatement and proof · cited by 32,603
- CategoryTheory.CategoryStruct.compstatement and proof · cited by 17,999
- CategoryTheory.Iso.homstatement and proof · cited by 7,684
- CategoryTheory.Isostatement and proof · cited by 3,963
- CategoryTheory.Preadditivestatement and proof · cited by 3,309
- CategoryTheory.IsIsostatement and proof · cited by 1,156
- CategoryTheory.Limits.biprodstatement and proof · cited by 312
- CategoryTheory.Limits.HasBinaryBiproductsstatement and proof · cited by 165
- CategoryTheory.Limits.biprod.sndproof · cited by 132
- CategoryTheory.Limits.biprod.inlstatement and proof · cited by 127
- CategoryTheory.Limits.biprod.fststatement and proof · cited by 121
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