Theorems · Theorem · measure theory
HasCompactSupport.stronglyMeasurable_of_prod
∀ {α : Type u_1} {X : Type u_5} {Y : Type u_6} [inst : Zero α] [inst_1 : TopologicalSpace X]
[inst_2 : TopologicalSpace Y] [inst_3 : MeasurableSpace X] [inst_4 : MeasurableSpace Y] [OpensMeasurableSpace X]
[OpensMeasurableSpace Y] [inst_7 : TopologicalSpace α] [TopologicalSpace.PseudoMetrizableSpace α] {f : X × Y → α},
Continuous f → HasCompactSupport f → MeasureTheory.StronglyMeasurable fA continuous function with compact support on a product space is strongly measurable for the product sigma-algebra. The subtlety is that we do not assume that the spaces are separable, so the product of the Borel sigma algebras might not contain all open sets, but still it contains enough of them to approximate compactly supported continuous functions.
- Cited by
- 1 results in Mathlib
- Foundations
- Depth 165 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
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Cites13
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- TopologicalSpacestatement and proof · cited by 24,529
- MeasurableSpacestatement and proof · cited by 13,106
- Continuousstatement and proof · cited by 2,592
- PseudoMetricSpaceproof · cited by 1,550
- OpensMeasurableSpacestatement and proof · cited by 636
- MeasureTheory.StronglyMeasurablestatement · cited by 363
- TopologicalSpace.PseudoMetrizableSpacestatement and proof · cited by 245
- HasCompactSupportstatement and proof · cited by 196
- TopologicalSpace.pseudoMetrizableSpacePseudoMetricproof · cited by 14
- stronglyMeasurable_iff_measurable_separableproof · cited by 13
- IsCompact.isSeparableproof · cited by 4
- HasCompactSupport.isCompact_rangeproof · cited by 4
Cited by1
Results whose statement or proof uses this declaration.
- MeasureTheory.integral_integral_swap_of_hasCompactSupportproof · cited by 2