Theorems · Theorem · field theory
IntermediateField.sup_toSubalgebra_of_isAlgebraic
∀ {K : Type u_3} {L : Type u_4} [inst : Field K] [inst_1 : Field L] [inst_2 : Algebra K L]
(E1 E2 : IntermediateField K L),
Algebra.IsAlgebraic K ↥E1 ∨ Algebra.IsAlgebraic K ↥E2 → (E1 ⊔ E2).toSubalgebra = E1.toSubalgebra ⊔ E2.toSubalgebraThe compositum of two intermediate fields is equal to the compositum of them as subalgebras, if one of them is algebraic over the base field.
- Cited by
- 3 results in Mathlib
- Foundations
- Depth 141 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites8
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Algebrastatement and proof · cited by 11,388
- Fieldstatement and proof · cited by 7,404
- Subalgebrastatement · cited by 1,353
- IntermediateFieldstatement and proof · cited by 988
- Algebra.IsAlgebraicstatement and proof · cited by 322
- IntermediateField.toSubalgebrastatement · cited by 134
- IntermediateField.sup_toSubalgebra_of_isAlgebraic_rightproof · cited by 6
- IntermediateField.sup_toSubalgebra_of_isAlgebraic_leftproof · cited by 2
Cited by3
Results whose statement or proof uses this declaration.
- IntermediateField.adjoin_intermediateField_toSubalgebra_of_isAlgebraicproof · cited by 5
- Algebra.TensorProduct.isField_of_isAlgebraicproof · cited by 2
- IntermediateField.rank_sup_le_of_isAlgebraicproof · cited by 1