Theorems · Theorem · group theory
IsFreeGroupoid.SpanningTree.loopOfHom_eq_id
∀ {G : Type u} [inst : CategoryTheory.Groupoid G] [inst_1 : IsFreeGroupoid G]
(T : WideSubquiver (Quiver.Symmetrify (IsFreeGroupoid.Generators G)))
[inst_2 : Quiver.Arborescence (WideSubquiver.toType (Quiver.Symmetrify (IsFreeGroupoid.Generators G)) T)]
{a b : IsFreeGroupoid.Generators G},
∀ e ∈ Quiver.wideSubquiverSymmetrify T a b,
IsFreeGroupoid.SpanningTree.loopOfHom T (IsFreeGroupoid.of e) =
CategoryTheory.CategoryStruct.id (IsFreeGroupoid.SpanningTree.root'✝ T)Turning an edge in the spanning tree into a loop gives the identity loop.
- Cited by
- 1 results in Mathlib
- Foundations
- Depth 17 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
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Cites24
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Setstatement · cited by 53,352
- Quiver.Homstatement and proof · cited by 32,603
- CategoryTheory.CategoryStruct.compproof · cited by 17,999
- CategoryTheory.Category.assocproof · cited by 6,433
- CategoryTheory.CategoryStruct.idstatement and proof · cited by 6,235
- CategoryTheory.Category.comp_idproof · cited by 2,119
- CategoryTheory.Category.id_compproof · cited by 1,998
- CategoryTheory.invproof · cited by 467
- CategoryTheory.Groupoidstatement and proof · cited by 182
- CategoryTheory.Endstatement and proof · cited by 169
- CategoryTheory.IsIso.inv_hom_idproof · cited by 88
- Quiver.Symmetrifystatement and proof · cited by 28
Cited by1
Results whose statement or proof uses this declaration.
- IsFreeGroupoid.SpanningTree.endIsFreeproof · cited by 0