Theorems · Theorem · field theory
IsGalois.card_aut_eq_finrank
∀ (F : Type u_1) [inst : Field F] (E : Type u_2) [inst_1 : Field E] [inst_2 : Algebra F E] [FiniteDimensional F E] [IsGalois F E], Nat.card Gal(E/F) = Module.finrank F E
Let $E / F$ be a finite extension of fields. If $E$ is Galois over $F$, then $|\text{Aut}(E/F)| = [E : F]$.
- Defined in
- Mathlib.FieldTheory.Galois.Basic
- Cited by
- 16 results in Mathlib
- Foundations
- Depth 156 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites39
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Algebrastatement and proof · cited by 11,388
- Top.topproof · cited by 9,680
- Fieldstatement and proof · cited by 7,404
- Algebra.algebraMapproof · cited by 4,706
- FiniteDimensionalstatement and proof · cited by 1,854
- Module.finrankstatement · cited by 1,770
- AlgEquivstatement and proof · cited by 1,681
- IntermediateFieldproof · cited by 988
- Nat.cardstatement and proof · cited by 844
- Polynomial.mapproof · cited by 806
- RingHomClass.toRingHomproof · cited by 746
- AlgEquiv.symmproof · cited by 615
Cited by16
Results whose statement or proof uses this declaration.
- NumberField.InfinitePlace.even_finrank_of_not_isUnramifiedproof · cited by 2
- IsGalois.fixedField_fixingSubgroupproof · cited by 2
- Ideal.card_stabilizer_eq_card_inertia_mul_finrankproof · cited by 2
- IsGalois.tfaeproof · cited by 2
- NumberField.IsCMField.isConj_eq_isConjproof · cited by 1
- IsGalois.finiteDimensional_of_finiteproof · cited by 1
- IntermediateField.finrank_eq_fixingSubgroup_indexproof · cited by 1
- exists_root_adjoin_eq_top_of_isCyclicproof · cited by 1
- Polynomial.Gal.card_of_separableproof · cited by 1
- NumberField.InfinitePlace.card_isUnramifiedproof · cited by 1
- NumberField.InfinitePlace.card_isUnramified_complproof · cited by 1
- NumberField.IsCMField.zpowers_complexConj_eq_topproof · cited by 1