Theorems · Theorem · optimization
IsLocalExtrOn.linear_dependent_of_hasStrictFDerivAt
∀ {E : Type u_1} [inst : NormedAddCommGroup E] [inst_1 : NormedSpace ℝ E] [CompleteSpace E] {φ : E → ℝ} {x₀ : E}
{φ' : StrongDual ℝ E} {ι : Type u_3} [Finite ι] {f : ι → E → ℝ} {f' : ι → StrongDual ℝ E},
IsLocalExtrOn φ {x | ∀ (i : ι), f i x = f i x₀} x₀ →
(∀ (i : ι), HasStrictFDerivAt (f i) (f' i) x₀) →
HasStrictFDerivAt φ φ' x₀ → ¬LinearIndependent ℝ (Option.elim' φ' f')Lagrange multipliers theorem. Let f : ι → E → ℝ be a finite family of functions.
Suppose that φ : E → ℝ has a local extremum on the set {x | ∀ i, f i x = f i x₀} at x₀.
Suppose that all functions f i as well as φ are strictly differentiable at x₀.
Then the derivatives f' i : E → L[ℝ] ℝ and φ' : StrongDual ℝ E are linearly dependent.
See also IsLocalExtrOn.exists_multipliers_of_hasStrictFDerivAt for a version that
that states existence of Lagrange multipliers Λ and Λ₀ instead of using
¬LinearIndependent ℝ _
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- Foundations
- Depth 185 from the axioms · uses propext, Classical.choice, Quot.sound
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- Realstatement and proof · cited by 25,697
- RingHom.idstatement · cited by 18,349
- NormedAddCommGroupstatement and proof · cited by 15,752
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- LinearIndependentstatement · cited by 560
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