Theorems · Theorem · general topology
IsUniformInducing.completeSpace_congr
∀ {α : Type u} {β : Type v} [inst : UniformSpace α] [inst_1 : UniformSpace β] {f : α → β},
IsUniformInducing f → Function.Surjective f → (CompleteSpace α ↔ CompleteSpace β)If f is a surjective uniform inducing map,
then its domain is a complete space iff its codomain is a complete space.
See also _root_.completeSpace_congr for a version that assumes f to be an equivalence.
- Cited by
- 6 results in Mathlib
- Foundations
- Depth 76 from the axioms · uses propext, Classical.choice, Quot.sound
- Assumes
- UniformSpaceUniformSpace
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites9
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Setproof · cited by 53,352
- Set.univproof · cited by 3,945
- CompleteSpacestatement and proof · cited by 2,532
- UniformSpacestatement and proof · cited by 2,040
- IsUniformInducingstatement and proof · cited by 128
- Function.Surjective.range_eqproof · cited by 70
- IsCompleteproof · cited by 68
- completeSpace_iff_isComplete_rangeproof · cited by 11
- completeSpace_iff_isComplete_univproof · cited by 5
Cited by6
Results whose statement or proof uses this declaration.
- completeSpace_congrproof · cited by 5
- ContinuousMultilinearMap.completeSpaceproof · cited by 1
- UniformConvergenceCLM.completeSpaceproof · cited by 1
- ContinuousAlternatingMap.completeSpaceproof · cited by 0
- SeparationQuotient.completeSpace_iffproof · cited by 0
- completeSpace_ulift_iffproof · cited by 0