Theorems · Theorem · probability
ProbabilityTheory.IsGaussian.map_rotation_eq_self_of_forall_strongDual_eq_zero
∀ {E : Type u_1} [inst : NormedAddCommGroup E] [inst_1 : NormedSpace ℝ E] [inst_2 : MeasurableSpace E] [BorelSpace E]
{μ : MeasureTheory.Measure E} [ProbabilityTheory.IsGaussian μ] [SecondCountableTopology E] [CompleteSpace E],
(∀ (L : StrongDual ℝ E), ∫ (x : E), L x ∂μ = 0) →
∀ (θ : ℝ), MeasureTheory.Measure.map (⇑(ContinuousLinearMap.rotation θ)) (μ.prod μ) = μ.prod μFor a centered Gaussian measure μ, the product measure μ.prod μ is invariant under rotation.
The hypothesis ∀ L : StrongDual ℝ E, μ[L] = 0 is equivalent to the simpler
μ[id] = 0, but at this point we don't know yet that μ has a first moment so we can't use it.
See map_rotation_eq_self.
- Cited by
- 2 results in Mathlib
- Foundations
- Depth 299 from the axioms · uses propext, Classical.choice, Quot.sound
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- Realstatement and proof · cited by 25,697
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- ProbabilityTheory.IsGaussian.exists_integrable_exp_sqproof · cited by 1
- ProbabilityTheory.IsGaussian.map_rotation_eq_selfproof · cited by 0