Projectivization.Subspace.span_union
∀ {K : Type u_1} {V : Type u_2} [inst : DivisionRing K] [inst_1 : AddCommGroup V] [inst_2 : Module K V]
(S T : Set (Projectivization K V)),
Projectivization.Subspace.span (S ∪ T) = Projectivization.Subspace.span S ⊔ Projectivization.Subspace.span TThe supremum of two subspaces is equal to the span of their union.
- Cited by
- 2 results in Mathlib
- Foundations
- Depth 85 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites10
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Setstatement and proof · cited by 53,352
- Modulestatement and proof · cited by 20,661
- AddCommGroupstatement and proof · cited by 12,871
- DivisionRingstatement and proof · cited by 1,062
- GaloisInsertion.gcproof · cited by 137
- Projectivizationstatement and proof · cited by 111
- GaloisConnection.l_supproof · cited by 81
- Projectivization.Subspacestatement · cited by 34
- Projectivization.Subspace.spanstatement · cited by 16
- Projectivization.Subspace.giproof · cited by 7
Cited by2
Results whose statement or proof uses this declaration.
- Projectivization.Subspace.sup_spanproof · cited by 0
- Projectivization.Subspace.span_supproof · cited by 0