Theorems · Inductive type · combinatorics
SimpleGraph.IsBipartiteWith
{V : Type u_1} → SimpleGraph V → Set V → Set V → PropG is bipartite in sets s and t iff s and t are disjoint and if vertices v and w
are adjacent in G then v ∈ s and w ∈ t, or v ∈ t and w ∈ s.
- Cited by
- 42 results in Mathlib
- Foundations
- Depth 1 from the axioms · uses no axioms
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites2
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Setstatement · cited by 53,352
- SimpleGraphstatement · cited by 3,072
Cited by45
Results whose statement or proof uses this declaration.
- SimpleGraph.IsBipartiteWith.disjointstatement and proof · cited by 11
- SimpleGraph.IsBipartiteWith.mem_of_adjstatement and proof · cited by 7
- SimpleGraph.IsBipartiteWith.isBipartitestatement and proof · cited by 3
- SimpleGraph.IsBipartiteWith.symmstatement and proof · cited by 3
- SimpleGraph.between_isBipartiteWithstatement · cited by 3
- SimpleGraph.isBipartiteWith_neighborSet_subsetstatement and proof · cited by 3
- SimpleGraph.IsBipartite.exists_isBipartiteWithstatement · cited by 2
- SimpleGraph.IsBipartiteWith.mem_of_mem_adjstatement and proof · cited by 2
- SimpleGraph.IsBipartiteWith.mem_of_mem_adj'statement and proof · cited by 2
- SimpleGraph.isBipartiteWith_neighborFinsetstatement and proof · cited by 2
- SimpleGraph.isBipartiteWith_neighborFinset'statement and proof · cited by 2
- SimpleGraph.union_eq_univ_of_forall_ncard_lestatement and proof · cited by 2