Theorems · Definition · number theory
rothNumberNat
ℕ →o ℕ
The Roth number of a natural N is the largest integer m for which there is a subset of
range N of size m with no arithmetic progression of length 3.
Trivially, rothNumberNat N ≤ N, but Roth's theorem (proved in 1953) shows that
rothNumberNat N = o(N) and the construction by Behrend gives a lower bound of the form
N * exp(-C sqrt(log(N))) ≤ rothNumberNat N.
A significant refinement of Roth's theorem by Bloom and Sisask announced in 2020 gives
rothNumberNat N = O(N / (log N)^(1+c)) for an absolute constant c.
- Cited by
- 17 results in Mathlib
- Foundations
- Depth 74 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites4
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- DFunLike.coeproof · cited by 62,936
- Finset.rangeproof · cited by 1,341
- OrderHomstatement · cited by 934
- addRothNumberproof · cited by 20
Cited by17
Results whose statement or proof uses this declaration.
- Behrend.bound_auxstatement and proof · cited by 1
- Behrend.bound_aux'statement and proof · cited by 1
- Behrend.card_sphere_le_rothNumberNatstatement and proof · cited by 1
- rothNumberNat_le_ruzsaSzemerediNumberNatstatement and proof · cited by 1
- rothNumberNat_le_ruzsaSzemerediNumberNat'statement and proof · cited by 1
- rothNumberNat_specstatement · cited by 1
- rothNumberNat_zerostatement · cited by 1
- Behrend.roth_lower_boundstatement and proof · cited by 1
- Behrend.roth_lower_bound_explicitstatement and proof · cited by 1
- ThreeAPFree.le_rothNumberNatstatement · cited by 1
- Fin.addRothNumber_eq_rothNumberNatstatement · cited by 1
- rothNumberNat_add_lestatement · cited by 0