Theorems · Definition · number theory
sigmaAntidiagonalEquivProd
(n : ℕ+) × ↥(↑n).divisorsAntidiagonal ≃ ℕ+ × ℕ+
The equivalence from the union over n of Nat.divisorsAntidiagonal n to ℕ+ × ℕ+
given by sending n = a * b to (a, b).
- Cited by
- 4 results in Mathlib
- Foundations
- Depth 69 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites6
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Finsetstatement · cited by 13,712
- Equivstatement · cited by 8,337
- PNatstatement and proof · cited by 392
- PNat.valstatement and proof · cited by 226
- Nat.divisorsAntidiagonalstatement and proof · cited by 61
- divisorsAntidiagonalFactorsproof · cited by 2
Cited by4
Results whose statement or proof uses this declaration.
- tsum_prod_pow_eq_tsum_sigmaproof · cited by 2
- summable_prod_mul_powproof · cited by 2
- sigmaAntidiagonalEquivProd_symm_apply_fststatement · cited by 0
- sigmaAntidiagonalEquivProd_symm_apply_sndstatement · cited by 0