Theorems · Theorem · commutative algebra
spectralAlgNorm_mul
∀ {K : Type u} [inst : NontriviallyNormedField K] {L : Type v} [inst_1 : Field L] [inst_2 : Algebra K L]
[inst_3 : Algebra.IsAlgebraic K L] [hu : IsUltrametricDist K] [CompleteSpace K] (x y : L),
(spectralAlgNorm K L) (x * y) = (spectralAlgNorm K L) x * (spectralAlgNorm K L) yIf K is a field complete with respect to a nontrivial nonarchimedean multiplicative norm and
L/K is an algebraic extension, then the spectral norm on L is multiplicative.
- Cited by
- 0 results in Mathlib
- Foundations
- Depth 229 from the axioms · uses propext, Classical.choice, Quot.sound
Around this declaration
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Cites23
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- DFunLike.coestatement and proof · cited by 62,936
- Realstatement · cited by 25,697
- Algebrastatement and proof · cited by 11,388
- NontriviallyNormedFieldstatement and proof · cited by 8,742
- Fieldstatement and proof · cited by 7,404
- CompleteSpacestatement and proof · cited by 2,532
- MulZeroClass.zero_mulproof · cited by 1,625
- map_zeroproof · cited by 1,614
- ne_of_gtproof · cited by 637
- le_of_eqproof · cited by 366
- Algebra.IsAlgebraicstatement and proof · cited by 322
- IsUltrametricDiststatement and proof · cited by 177
Cited by1
Results whose statement or proof uses this declaration.
- spectralMulAlgNormproof · cited by 5