Theorems · Theorem · group theory
IsFreeGroupoid.SpanningTree.treeHom_eq
∀ {G : Type u} [inst : CategoryTheory.Groupoid G] [inst_1 : IsFreeGroupoid G]
(T : WideSubquiver (Quiver.Symmetrify (IsFreeGroupoid.Generators G)))
[inst_2 : Quiver.Arborescence (WideSubquiver.toType (Quiver.Symmetrify (IsFreeGroupoid.Generators G)) T)] {a : G}
(p : Quiver.Path (Quiver.root (WideSubquiver.toType (Quiver.Symmetrify (IsFreeGroupoid.Generators G)) T)) a),
IsFreeGroupoid.SpanningTree.treeHom T a = IsFreeGroupoid.SpanningTree.homOfPath T pAny path to a gives treeHom T a, since paths in the tree are unique.
- Cited by
- 2 results in Mathlib
- Foundations
- Depth 15 from the axioms · uses Classical.choice
Around this declaration
Dashed lines are statement dependencies; solid lines are citations in proofs.
Cites13
Mathlib declarations this one mentions in its statement or cites explicitly in its proof. Plumbing is filtered out.
- Quiver.Homstatement and proof · cited by 32,603
- CategoryTheory.Groupoidstatement and proof · cited by 182
- Quiver.Pathstatement and proof · cited by 166
- Quiver.Symmetrifystatement and proof · cited by 28
- IsFreeGroupoid.Generatorsstatement and proof · cited by 11
- IsFreeGroupoidstatement and proof · cited by 11
- Quiver.Arborescencestatement and proof · cited by 7
- WideSubquiver.toTypestatement and proof · cited by 7
- WideSubquiverstatement and proof · cited by 7
- IsFreeGroupoid.SpanningTree.homOfPathstatement and proof · cited by 4
- IsFreeGroupoid.SpanningTree.treeHomstatement · cited by 4
- Unique.default_eqproof · cited by 3
Cited by2
Results whose statement or proof uses this declaration.
- IsFreeGroupoid.SpanningTree.treeHom_rootproof · cited by 1
- IsFreeGroupoid.SpanningTree.loopOfHom_eq_idproof · cited by 1